Difference between revisions of "Solução: Problema da simplificação das frações (Bruno Barbosa)"
From AdonaiMedrado.Pro.Br
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int analisaImprime(int i, int x, int y){ | int analisaImprime(int i, int x, int y){ | ||
− | + | ||
while((x%i!=0)||(y%i!=0)){ | while((x%i!=0)||(y%i!=0)){ | ||
i--; | i--; | ||
Line 26: | Line 26: | ||
if(!n || !m) | if(!n || !m) | ||
printf("%d %d\n", n, m); | printf("%d %d\n", n, m); | ||
− | + | ||
− | + | else | |
analisaImprime(n, n, m); | analisaImprime(n, n, m); | ||
− | + | ||
scanf("%d %d", &n, &m); | scanf("%d %d", &n, &m); | ||
} | } |
Revision as of 12:13, 6 June 2009
#include <stdio.h> int analisaImprime(int num, int x, int y); int analisaImprime(int i, int x, int y){ while((x%i!=0)||(y%i!=0)){ i--; } if((x%i == 0)&&(y%i==0)) printf("%d %d\n", x/i, y/i); else printf("%d %d\n", x, y); } int main(){ int n, m; scanf("%d %d", &n, &m); while(n || m){ if(!n || !m) printf("%d %d\n", n, m); else analisaImprime(n, n, m); scanf("%d %d", &n, &m); } }